96p+105+15p^2=0

Solution for 96p+105+15p^2=0 equation:

96p+105+15p^2=0

a = 15; b = 96; c = +105;
Δ = b2-4ac
Δ = 962-4·15·105
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-54}{2*15}=\frac{-150}{30}
=-5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+54}{2*15}=\frac{-42}{30}
=-1+2/5
$